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So just as I was about to pull the trigger on cancelling my/reordering my debit, CDL and OneStop card, I thought ... "Let's go to the records ... I deposited about $200 on Friday, no checking action Saturday (as I did not leave the house). Sunday I went two places; the WF ATM across the st. ... + the Starbucks adjacent (forgive me dear reader, but after 6 years on 'n off employment their in HS and early college ... I am hopelessly addicted to their South American beans. Colombia, Guatemala, House Blend (fun fact - they just stir the Gust and Colombia together; that's what "House Blend" is) and now Pike Place Roast, also a SA concoction, do not quote me on this but I think all they did was adjust the Col to Gua ratio and roast the beans SLIGHTLY longer.

Anyway I see that the only two places I have gone in many days in WF ATM and TakeBucks. So I went in today, ordered a Grande South American Blend + cheese danish and inquired about the lost wallet, I had decided to see if I could brush up on my math skills, so w/ a book and some scartch papel en mano .... I found an empty table (rare) and dropped my detritus on or near the table - there was a chance that the wallet could've fallen and been forgotten by me or fell out of my pocket or what have you .... yep, they had it! Nice. "Um yes super-thin black wallet? Fake plastic vinyl? No $ in it? Contains 1 debit, 1 CDL and my "officially-state-verified-and-sponsored loser card? Chris Welke? or Christopher Ernest?

Ahh.... my life was for a very brief moment, complete.

BTW - that day I brushing up on my graduate-level math skills by attempting to prove two axioms, one carefully guarded by the Pythagoreans and considered sacred, the other on the same level; by Plato and his ppl; Archimedes et al.

1. Prove that all right triangle's: (ex below) 

(thx to efg2.com)

Where, by def; the length of x,y=1 and angle{x,y} = 90 degrees, have a hypotenuse h.

h= sqrt(2), 

Prove: sqrt(2) belongs to the set of Irrational numbers. That is, there are no two integers, I'll just call them p,q that when expressed as p/q (p, q !=0) and p, q have now common denominator. This is is proved by an ancient technique known by the latin contemporaries who discovered it as reductio ad absurdum. Don't worry I won't bore u w/ the actual proof, over your head or not? It is only interesting to geeks como yo. :)

Much more difficult was: Prove that there exists 5 and only 5 regular Platonic solids. Ex: dice are regular Platonic solids because: 1. all edges are of equal length, all veritices are of = angle and the area each face in =. hope I am not forgetting something.

They are the elegant, sacred Platonic Solids:* Tetrahedron, Cube, Icosahedron, Octahedron and the Dodecahedron. I should win an award for using "dodecahedron" in a sentence). plz send $$$ in lieu of plaques or flowers or ... thx.

It's all based on the fact that a regular solid has the following property: vertices - edges + faces = 2.

Again I was pretty d*** proud of my myself when I solved it, so excited in fact that I left sans walleto.

RE: my Weiner preDiction ...looks like I'm nearly on the mark, the only question is how far off the mark I will be KFI and KFWB both reported the Dem leaders in C were "lining up to call to for his resignation." Weiner told the press he is "waiting for his wife to come home."

Translation: he needs her @his side when he calls that resignation-press-conf I told you about last week. (He wants her at his side during the speech, like Kobe and the $4million pink diamond ring. 'Cept Weiner don't have that kimnda jack homie!!! So plz tell me you would hire me over him and his dinky PS BS.

I don't know something tells me that I will have to worry about finances than Weiner. Or Weiner's weiner for that matter. And thank you for introducing 'sext' into the official lexicon of American English. We are becoming a better society each day.